Distance formula 3d

yeah

dist = sqrt((x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2)



...go on and live with no regrets, you only have one life...

Simple=)
deltax=x2-x1;
deltay=y2-y1;
deltaz=z2-z1;
distance=sqrt((deltax*deltax)+(deltay*deltay)+(deltaz*deltaz))


;-)

Raymond Jacobs,
Developer,
www.EtherealDarkness.com

Thanks. I thought it might be something like that, but I wasn''t sure.

-treknerd

glad to help.... FIRST!

...go on and live with no regrets, you only have one life...

yeah, you replied 4 minutes after my post. That''s really quick!

On the tail end of this animal
I have a question on how distance in world space relates to screen space


Let see if I can get my point across correctly
You have a line segment represented by 3d endpoints A and B
its the distance between these points we''ll denote as Lw
(Length in World Space) but I need to know what the segments Ls
(Length in Screen Space) is basically its length in pixels

if the Z axis is perpendicular to the view plane (monitor) then as Segment AB''s Z increases or decreses the distance between A&B will always be Lw but Ls is going to change.

In otherwords it takes more pixels to represent a line as it gets closer to the eye and less further away

Things I already know
screen resolution and aspect ratio are going to have an impact on this relationship.

10Q in Advanced


No Matter what it is (programming related)...Some Assembly Required.