Quote:
Original post by KulSeran
1) your question doesn't make much sense.
2) in c, the keyword 'void' is a type, just like int, float, double, char. 'void' represents "no type". It can be used to indicate a function has no return value, and if you really want to, to indicate a function takes no parameters
"void foo(void) {}"
Quote:Have you actually covered the topic of functions in your book? If you haven't, "calling functions" is also going to be a completely alien topic.
what i mean is im trying to make a game and i cant make sub-menus and some one mentioned calling function whats that then?
Quote:What's the point of a function in the first place?
so the void "type" whats so good about it if it represents a "no type"
Quote:
...so the void "type" whats so good about it if it represents a "no type"
Quote:
Original post by oler1s Quote:Have you actually covered the topic of functions in your book? If you haven't, "calling functions" is also going to be a completely alien topic.
what i mean is im trying to make a game and i cant make sub-menus and some one mentioned calling function whats that then?
If you have, here's an exercise for you. Write a function that adds two integers. Show us code that uses this function to add 5 and 6.Quote:What's the point of a function in the first place?
so the void "type" whats so good about it if it represents a "no type"
Quote:
Original post by CodeCriminal
Well, to actual programmers "calling function" could be percieved as the act of calling 'a/the' function(s), but in the context of your first post it sounds as though you are talking about the 'return' type of a function. In that case then, 'void' can be used and means that a given function 'foo' does not return a value.
As for your sub-menu system, I have no idea what your talking about, your description is nothing short of poor, lacking information and clarification to appropriatly deduce what your problem is, or may be.
Please elaborate on the following quotations:
. "..if statement can go so far.."
. "..sub menu for one of my menus menus.."Please could you use a slightly more clearer, more formal approach in your posts, 'cuz' and 'plz' are not words. That may seem a bit nit-picky, however writing with correct spelling and grammer help to convey meaning, thus allowing others to help you with your programming troubles.
Good luck.
Quote:
Original post by cocopuffs Quote:
Original post by CodeCriminal
Well, to actual programmers "calling function" could be percieved as the act of calling 'a/the' function(s), but in the context of your first post it sounds as though you are talking about the 'return' type of a function. In that case then, 'void' can be used and means that a given function 'foo' does not return a value.
As for your sub-menu system, I have no idea what your talking about, your description is nothing short of poor, lacking information and clarification to appropriatly deduce what your problem is, or may be.
Please elaborate on the following quotations:
. "..if statement can go so far.."
. "..sub menu for one of my menus menus.."Please could you use a slightly more clearer, more formal approach in your posts, 'cuz' and 'plz' are not words. That may seem a bit nit-picky, however writing with correct spelling and grammer help to convey meaning, thus allowing others to help you with your programming troubles.
Good luck.
here ill just copy/paste what i have so far.
#include "stdafx.h"
#include "iostream"
#include "ctime"
#include "stdio.h"
int main()
{
using namespace std;
int menu;
do
{
cout << "==============================" << endl;
cout << "|| MAIN MENU ||" << endl;
cout << "==============================" << endl;
cout << "||Please make a selection: ||" << endl;
cout << "||1. create a character ||" << endl;
cout << "||2. shop ||" << endl;
cout << "||3. view stats ||" << endl;
cout << "||4. enter death arena ||" << endl;
cout << "||5. quit game ||" << endl;
cout << "============================== \n" << endl;
cin >> menu;
} while (menu != 1 && menu != 2 &&
menu != 3 && menu != 4 && menu != 5);
switch (menu)
{
case 1:
int nameYourCharacter = 1;
// sub menu character
cout << "" << endl; // space to look better
cout << "==============================" << endl;
cout << "|| CHARACTER MENU ||" << endl;
cout << "==============================" << endl;
cout << "||1. name your character ||" << endl;
cout << "||2. roll for stats ||" << endl;
cout << "||3. back to main menu ||" << endl;
cout << "============================== \n" << endl;
break;
break;
case 2:
//sub menu shop
cout << "" << endl; // space to look better
cout << "==============================" << endl;
cout << "|| SHOP MENU ||" << endl;
cout << "==============================" << endl;
cout << "||1. purchase armor ||" << endl;
cout << "||2. purchase weapon ||" << endl;
cout << "||3. back to main menu ||" << endl;
cout << "==============================" << endl;
break;
case 3:
//sub menu shop
cout << "" << endl; // space to look better
cout << "==============================" << endl;
cout << "|| VIEW STATS ||" << endl;
cout << "==============================" << endl;
cout << "||1. name: ||" << endl;
cout << "||2. level: ||" << endl;
cout << "||3. strength: ||" << endl;
cout << "||4. dexterity: ||" << endl;
cout << "||5. constitution: ||" << endl;
cout << "||6. HP: ||" << endl;
cout << "||7. exp: ||" << endl;
cout << "||8. gold: ||" << endl;
cout << "||9. exit menu ||" << endl;
cout << "==============================" << endl;
break;
}
return 0;
}
what i mean by "if()" is that u can only do if and else, i think this is ok to do but correct me if im wrong, could i nest if statements or switch?
and by what i mean by menus for my menus is this main menu -> equipment and then -> weapons
sorry for the grammar im too used to texting.
Quote:What do you mean somewhat? Either you've touched the topic, or you haven't. There's no ambiguity in what a function is.
i some what have so far im near the array parts i havent gatten to far into it tho and i havent practiced it but i get most of it
Quote:No. It doesn't look like you've touched on the topic at all. Thus, you shouldn't worry about functions until you reach that point in your book. Focus on learning what the book shows you, and progress step by step. Don't worry about what someone else knows and would do. You are not him.
idk if this is wrong but is this what u mean?
Quote:As a note, you want to write
here ill just copy/paste what i have so far.
case 99: //oneline; break;case 98:{ //line 1; //line 2; //etc.; break;}Quote:Yes.
what i mean by "if()" is that u can only do if and else, i think this is ok to do but correct me if im wrong, could i nest if statements?
#include <iostream>int main(int, char**){ int x = 1, y = 0; // && (Logical AND operator) - evaluate multiple arguments, the if statement will process if the expression evauluates to 'true' if (x == 1 && y == 0) std::cout << "Logical AND" << std::endl; // || (Logical OR operator) - evaluate multiple arguments, the if statement will process if the one of two evaluate to 'true' if (x == 1 || y == 1) std::cout << "Logical OR" << std::endl; // ! (Logical NOT operator) - evaluate argument, will evaluate to true if the expression is false. if (y != 1) std::cout << "Logical NOT" << std::endl; // Nesting if statements if (x == 1) if (y == 0) std::cout << "Nesting without braces" << std::endl; if (x == 1) { if (y == 0) { std::cout << "Nesting with braces" << std::endl; } } return 0;}Quote:
Original post by oler1s Quote:What do you mean somewhat? Either you've touched the topic, or you haven't. There's no ambiguity in what a function is.
i some what have so far im near the array parts i havent gatten to far into it tho and i havent practiced it but i get most of it Quote:No. It doesn't look like you've touched on the topic at all. Thus, you shouldn't worry about functions until you reach that point in your book. Focus on learning what the book shows you, and progress step by step. Don't worry about what someone else knows and would do. You are not him.
idk if this is wrong but is this what u mean? Quote:As a note, you want to write
here ill just copy/paste what i have so far. , , and , not "iostream", "ctime", and "stdio.h".
Your switch/case blocks have a problem. For each case, you have one of two options. You can either have a single statement, or you can have a compound statement. Example:case 99: //oneline; break;
Or:case 98:{ //line 1; //line 2; //etc.; break;}
Your book should have shown you this distinction. Pay attention to such details. Things like braces and semicolons matter.Quote:Yes.
what i mean by "if()" is that u can only do if and else, i think this is ok to do but correct me if im wrong, could i nest if statements?
I can't comment on your code indentation. It's not preserved because you failed to post in CODE or SOURCE tags.
Quote:
Original post by CodeCriminal
Yes you can absolutly nest if statements, not only that but you can create if statements that check multiple 'arguments' with the use of logical operators.
Here are some examples:
*** Source Snippet Removed ***
Try building that code to see the outcome.
Quote:
Original post by oler1s
Your switch/case blocks have a problem. For each case, you have one of two options. You can either have a single statement, or you can have a compound statement. Example:case 99: //oneline; break;
Or:case 98:{ //line 1; //line 2; //etc.; break;}
Your book should have shown you this distinction. Pay attention to such details. Things like braces and semicolons matter.
case 1:case 2:case 3:case 4: DoSomething(); break;//Admittedly this function has no real purpose, but we wanted to gauge your knowledge.//The arguments are listed as "void" because it doesn't take any arguments.int AddNumbers( void ){ return 5 + 6;}//A more practical helper functionint AddNumbers( int nArg1, int nArg2 ){ return nArg1 + nArg2;}//How you would call said functionint main( void ){ ... int nResult = AddNumbers(5, 6); //nResult should be assigned the value of 11 ...}//A function that doesn't return any values (hence a void return type)void PrintName( void ){ cout << "Name";}Quote:
Original post by dclyde
//The arguments are listed as "void" because it doesn't take any arguments.
int AddNumbers( void )
Quote:
Original post by hasonish
I swear to god I've seen this code before, as if somebody else has posted it...*starts rummaging through the forum history*
Ah, found it: here
You had already posted this before, and we actually gave you some pretty good suggestions in the last thread.
I don't see why you didn't take the suggestions, as they were very helpful. =/
Quote:
Original post by cocopuffs
Sry my friend was the one who posted it for me and then he didn't tell me anything after that so I didn't know he got a respond thanks for the link though, that seemed to help
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